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f(x)=16=+0x-x^2.Find range of function (assuming a domain of all x).Let A,B & state if endpoints are infinite?
Clearly there is no real number for which f(x) doesn't exist. Therefore, f(x) spans the set of real numbers.
For endpoints since 0x - x^2 = - X^2
f(x) = - x^2. Since x^2 is always positive (the square of any number is positive), then the presnce of "-" makes f(x) always negative.
That is f(x) = -x^2 ranges from negative infinity to 0
Range f(x) = (-oo, 0] *** -oo means negative infinity
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